10^(2x)+4*10^(x)=21

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Solution for 10^(2x)+4*10^(x)=21 equation: 



10^(2x)+4*10^(x)=21

We move all terms to the left:

10^(2x)+4*10^(x)-(21)=0

Wy multiply elements

10^2x+40x-21=0

We add all the numbers together, and all the variables

40x+10^2x-21=0

We move all terms containing x to the left, all other terms to the right

40x+10^2x=21

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